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Byju's Answer
Standard XII
Mathematics
Determinant
Solve: [ 1 ...
Question
Solve:
⎡
⎢
⎣
1
4
2
2
−
1
4
−
3
7
6
⎤
⎥
⎦
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Solution
we have
⎡
⎢
⎣
1
4
2
2
−
1
4
−
3
7
6
⎤
⎥
⎦
now
Δ
=
∣
∣ ∣
∣
1
4
2
2
−
1
4
−
3
7
6
∣
∣ ∣
∣
Expanding the given determinant by
1
s
t
row, we get
Δ
=
1
∣
∣
∣
−
1
4
7
6
∣
∣
∣
−
4
∣
∣
∣
2
4
−
3
6
∣
∣
∣
+
∣
∣
∣
2
−
1
−
3
7
∣
∣
∣
=
1
(
−
6
−
28
)
−
4
(
12
+
12
)
+
2
(
14
−
3
)
=
−
34
−
96
+
22
=
−
130
+
22
=
−
108
Hence,
Δ
=
−
108
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