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Byju's Answer
Standard XII
Mathematics
Determinant
Solve: [ 2 ...
Question
Solve:
⎡
⎢
⎣
2
−
1
4
4
−
3
1
1
2
1
⎤
⎥
⎦
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Solution
We have
⎡
⎢
⎣
2
−
1
4
4
−
3
1
1
2
1
⎤
⎥
⎦
Now
Δ
=
∣
∣ ∣
∣
2
−
1
4
4
−
3
1
1
2
1
∣
∣ ∣
∣
Expanding the given determinant by
1
s
t
row, we get
Δ
=
2
∣
∣
∣
−
3
1
2
1
∣
∣
∣
+
1
∣
∣
∣
4
1
1
1
∣
∣
∣
+
4
∣
∣
∣
4
−
3
1
2
∣
∣
∣
=
2
(
−
3
−
2
)
+
1
(
4
−
1
)
+
(
8
+
3
)
=
−
10
+
3
+
44
Δ
=
37
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