Solve 4 3 m- 3 4 n 2 -2mn- 16 9 m 2 - 9 16 n 2

LHS =( 4 3 m 3 4 n ) #160; ^ 2 +2mn = 16 9 m ^ 2 + 9 16 n ^ 2 2( 4 3 m. 3 4 n ) +2mn = 16 9 m ^ 2 + 9 16 n ^ 2 2mn+2mn ...

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Laws of Exponents for Real Numbers

Solve 4 3 ...

Question

Solve ${(\frac{4}{3} m - \frac{3}{4} n)}^{2} + 2 m n = \frac{16}{9} m^{2} + \frac{9}{16} n^{2}$

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Solution

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Similar questions

{(\frac{4}{3} m - \frac{3}{4} n)}^{2} + 2 m n = \frac{16}{9} m^{2} + \frac{9}{16} n^{2}

{(\frac{4}{3} m - \frac{3}{4} n)}^{2} + 2 m n = \frac{16}{9} m^{2} + \frac{9}{16} n^{2}

Question 5(iii)
Show that:
${(\frac{4}{3} m - \frac{3}{4} n)}^{2} + 2 m n = \frac{16}{9} m^{2} + \frac{9}{16} n^{2}$

Question 5(iii)
Show that:
${(\frac{4}{3} m - \frac{3}{4} n)}^{2} + 2 m n = \frac{16}{9} m^{2} + \frac{9}{16} n^{2}$

Show that

(i) (3x + 7)² − 84x = (3x − 7)²(ii) (9p − 5q)² + 180pq = (9p + 5q)²

(iii)

(iv) (4pq + 3q)²− (4pq − 3q)² = 48pq²

(v) (a − b) (a + b) + (b − c) (b + c) + (c − a) (c + a) = 0

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