Question

Solve ${\left(\frac{2}{8}\right)}^{2x}\times {\left(\frac{2}{8}\right)}^x={\left(\frac{2}{8}\right)}^6$

Answer 1

${\left(\frac{2}{8}\right)}^{2x}\times {\left(\frac{2}{8}\right)}^x={\left(\frac{2}{8}\right)}^6$
${\left(\frac{2}{8}\right)}^{2x+x}={\left(\frac{2}{8}\right)}^6(\because$ The base on both sides are equal)
$2x+x=6$
$3x=6$
$x=\frac{6}{3}=2$.