Solve - 2n2n - 1p - 11 - p2np

( 2n2n 1 )^P= ( 11 P2n )^P ⇒2n(2n 1)=1(1 P2n) ⇒ 2n ( 1 P2n ) = ( 2n 1) ⇒ 2n P=2n 1 p=1 ...

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(a-b)^2 Expansion and Visualisation

Solve : 2n2...

Question

Solve : ${(\frac{2 n}{2 n - 1})}^{p} = {⎛ ⎜ ⎜ ⎝ \frac{1}{1 - (\frac{p}{2 n})} ⎞ ⎟ ⎟ ⎠}^{p}$

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Solution

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Similar questions

\frac{16 \times 2^{n + 1} - 4 \times 2^{n}}{16 \times 2^{n + 2} - 2 \times 2^{n + 2}}

\frac{1}{3.5} + \frac{1}{5.7} + \frac{1}{7.9} + . . . + \frac{1}{(2 n + 1) (2 n + 3)} = \frac{n}{3 (2 n + 3)}

lim n \to \infty \frac{1 + 3 + 5 + \dots . . . + . (2 n - 1)}{2 + 4 + 6 + . . + 2 n}

^{2 n + 1} P_{n - 1} :^{2 n - 1} P_{n} = 3 : 5

n = ?

P (2 n - 1, n) : P (2 n + 1, n - 1) = 22 : 7

n

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