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Question

Solve:
(sinmxsinnx)m+n.(sinnxsinqx)n+q(sinqxsinmx)q+m

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Solution

Let
P=(sinmxsinnx)m+n(sinnxsinqx)n+q(sinqxsinmx)q+m
P=(sinx)(mn)(m+n).(sinx)(nq)(n+q).(sinx)(qm)(q+m)
P=(sinx)m2n2+n2q2+q2m2=(sinx)0=1

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