Question

Solve ${[i^{17}-{\left(\frac{1}{i}\right)}^{34}]}^2$

Answer 1

$\to {(i^{17}-{\left(\frac{1}{i}\right)}^{34})}^2={(i^{16}.i-\frac{1}{i^{32}.i^2})}^2$

$i^{4k}=1,i^{4k+2}=i^2=-1$

$\to (i-\frac{1}{-1})=i+1=1+i$