Question

solve : ${\left[{\left\{{\left(\frac{-1}{3}\right)}^2\right\}}^{-2}\right]}^{-1}$

Answer 1

$\begin{array}{c}Wehave\\ {\left[{\left\{{\left(\frac{-1}{3}\right)}^2\right\}}^{-2}\right]}^{-1}\\ ={\left[{\left\{\frac{1}{9}\right\}}^{-2}\right]}^{-1}\left[{\left(\frac{a}{b}\right)}^{-1}=\frac{b}{a}\right]\\ ={\left[{\left\{\frac{9}{1}\right\}}^2\right]}^{-1}\\ ={\left[81\right]}^{-1}\\ =\frac{1}{81}\\ Itistherequiredanswer.\end{array}$