Solve: $(x + 1) (2 x - 1) - 5 x = (2 x - 3) (x - 5) + 47$

Open in App

Solution

Given, $(x + 1) (2 x - 1) - 5 x = (2 x - 3) (x - 5) + 47$

$\Rightarrow x (2 x - 1) + 1 (2 x - 1) - 5 x = 2 x (x - 5) - 3 (x - 5) + 47$

$\Rightarrow 2 x^{2} - x + 2 x - 1 - 5 x = 2 x^{2} - 10 x - 3 x + 15 + 47$

$\Rightarrow 2 x^{2} - 4 x - 1 = 2 x^{2} - 13 x + 62$

$\Rightarrow - 4 x - 1 = - 13 x + 62$

$\Rightarrow - 4 x + 13 x = 62 + 1$

$\Rightarrow 9 x = 63$

$\Rightarrow x = \frac{63}{9} = 7$

$∴ x = 7$

Suggest Corrections

Similar questions

3 (x + 3) - 2 (x - 1) = 5 (x - 5)

\sqrt{(2 x + 5)} + \sqrt{(5 x + 6)} = \sqrt{(12 x + 25)}

Question 63

Solve the following:

$\frac{1}{2} (x + 1) + \frac{1}{3} (x - 1) = \frac{5}{12} (x - 2)$

\sqrt{2 x + 5} + \sqrt{5 x + 6} = \sqrt{12 x + 25}

\frac{2 x^{3} - 3 x^{2} + x + 1}{2 x^{3} - 3 x^{2} - x - 1} = \frac{3 x^{3} - x^{2} + 5 x - 13}{3 x^{3} - x^{2} - 5 x + 13}

Join BYJU'S Learning Program