Solve $(x + 2) (x + 3) + (x - 3) (x - 2) - 2 x (x + 1) = 0$

Open in App

Solution

$(x + 2) (x + 3) + (x - 3) (x - 2) - 2 x (x + 1) = 0$

$x^{2} + 5 x + 6 + x^{2} - 5 x + 6 - 2 x^{2} - 2 x = 0$

$12 - 2 x = 0$

$∴ x = 6$

Suggest Corrections

Similar questions

(x + 2) (x + 3) + (x - 3) (x - 2) - 2 x (x + 1) = 0

(x + 2) (x + 3) + (x - 3) (x - 2) - 2 x (x + 1) = 0

Find the value of $x : (x + 2) (x + 3) + (x - 3) (x - 2) - 2 x (x + 1) = 0$

Solve each of the following equations and also verify your solution :

(x + 2)(x+3)+(x-3)(x-2)-2x(x+1)=0

Join BYJU'S Learning Program