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Question

Solve: lim x->1 (2x2-5x+4)/(5x2-2x-3)

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Solution

Use L Hospitals rule.

Differentiate nuumerator and denominator seperatly.

d/dx (Numerator) = 4x-5
d/dx ( denominator) = 10x-2

now the limit becomes,
lim x---> 1 (4x-5) / (10x-2)
= (4-5) / (10-2)
= -1/ 8

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