Question

Solve:

${lim}_{x\to 3}\frac{x^2-9}{x-3}$

Answer 1

We have,

${lim}_{x\to 3}\frac{x^2-9}{x-3}$

${lim}_{x\to 3}\frac{x^2-3^2}{x-3}$

${lim}_{x\to 3}\frac{(x-3)(x+3)}{x-3}$

${lim}_{x\to 3}(x+3)$

$=(3+3)=6$

Hence, this is the answer.