Question

Solve linear equation:
$\frac{x-5}{3}=\frac{x-3}{5}$

Answer 1

$\frac{x-5}{3}=\frac{x-3}{5}$
Multiply both sides by $15$, we will get
$\frac{x-5}{3}\times 15=\frac{x-3}{5}\times 15$
$5(x-5)=3(x-3)$
$5x-25=3x-9$
Transpose $25$ to RHS and $3x$ to LHS
We will get,
$5x-3x=25-9$
$2x=16$
$x=\frac{16}{2}$
$x=8$