wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve
log2(2x2)log2(16x)=92log22x

Open in App
Solution

log2(2x2)log2(16x)=92log22x
(log22+2log2x)(4log22+log2x)=92(log2x)2
(1+2log2x)(4+log2x)=92(log2x)2
2(log2x)2+9(log2x)+4=92(log2x)2
4(log2x)2+18(log2x)+8=9(log2x)2
5(log2x)218(log2x)8=0
5(log2x)220log2x+2log2x8=0
5log2x(log2x4)+2(log2x4)=0
(log2x4)(5log2x+2)=0
log2x=4
x=24
x=16
And, 5log2x+2=0
x=22/5
So, x=16,22/5

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Property 1
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon