Solve ${log}_{3} ({log}_{2} x) = 1$

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Solution

Let ${log}_{2} x = y$
Then, ${log}_{3} y = 1$
$3^{1} = y$ (exponential form)
$∴ y = 3$
Put $y = 3$ in (1). Then ${log}_{2} x = 3$
$2^{3} = x$ (exponential form)
$∴ x = 8$

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