Question

Solve: $\log (3x+2)+\log (3x-2)=\log 5$

Answer 1

$\log (3x+2)+\log (3x-2)=\log 5$

or, $\log \left\{\right(3x+2\left)\right(3x-2\left)\right\}=\log 5$ [Using product rule of logarithm]

or, $9x^2-4=5$

or, $9x^2=9$

or, $x^2=1$

or, $x=\pm 1$.