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Byju's Answer
Standard VIII
Mathematics
Multiplication of Monomials
Solve: log7...
Question
Solve:
log
7
log
5
(
√
x
+
5
+
√
x
)
=
0
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Solution
log
7
log
5
(
√
x
+
5
+
√
x
)
=
0
log
5
(
√
x
+
5
+
√
x
)
=
7
2
=
1
√
x
+
5
+
√
x
=
5
x
+
5
+
x
+
2
√
x
√
x
+
5
=
25
2
x
+
5
+
2
√
x
√
x
+
5
=
25
2
√
x
√
x
+
5
=
20
−
2
x
√
x
√
x
+
5
=
10
−
x
x
(
x
+
5
)
=
100
+
x
2
−
20
x
x
2
+
5
x
=
x
2
−
20
x
+
100
25
x
=
100
x
=
4
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0
Similar questions
Q.
The solution of the equation
log
7
log
5
(
√
x
+
5
+
√
x
)
=
0
is....
Q.
The solution of the equation
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