Solve: $l o g (\frac{e^{x}}{x^{2}})$

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Solution

$log (\frac{e^{x}}{x^{2}}) = log e^{x} - log x^{2} = x - 2 log x$

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Similar questions

\frac{1 + log e^{x}}{1 - log e^{x}}

x d y = (y + x y^{3} (1 + {log}_{e} x)) d x

f (x) = {log}_{e} (x + \sqrt{x^{2} + 1})

y = {log}_{e} (x + \sqrt{x^{2} - a^{2}})

\frac{d y}{d x}

\frac{d y}{d x}

y = {log}_{e} (x + \sqrt{x^{2} - a^{2}})

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