Question

Solve: $\log (2+2\log (1+x))=0$

• A. $\frac{10}{9}$
• B. $\frac{-10}{9}$
• C. $\frac{9}{10}$
• D. $\frac{-9}{10}$

Answer 1

The correct option is D $\frac{-9}{10}$

$\log (2+2\log (1+x\left)\right)=0$

$\Rightarrow 2+2\log (1+x)=1$

$\Rightarrow \log (1+x)=-1$

$\Rightarrow 1+x=\frac{1}{10}$

$\Rightarrow x=-\frac{9}{10}$