Question

Solve; $\log \left(x+1\right)-\log \left(x-1\right)=1$

Answer 1

Solution-

$\log (x+1)-\log (x-1)=1$

$\log \left(\frac{x+1}{x-1}\right)=1$

Suppose $\log$ is on base $10$.

Antilog both sides.

$\frac{x+1}{x-1}={10}^1$

$x+1=10x-10$

$11=9x$

$x=\frac{11}{9}$