Question

Solve: ${\log }_s\left(\frac{2+x}{10}\right)={\log }_s\left(\frac{2}{x+1}\right)$

Answer 1

Let the

${\log }_s\left(\frac{2+x}{10}\right)={\log }_s\left(\frac{2}{x+1}\right)$

$\Rightarrow$ $\left(\frac{2+x}{10}\right)=\left(\frac{2}{x+1}\right)$

$\Rightarrow$$x^2+3x-18=0$

$\Rightarrow$$\left(x-3\right)\left(x+6\right)=0$

$\Rightarrow$$x=3,x=-6$