Question

Solve ${\left(\log \right(x^2-2x+1\left)\right)}^{-1}=$

Answer 1

Solution:-

${\left(\log (x^2-2x+1)\right)}^{-1}$

$={\left(\log {(x-2)}^2\right)}^{-1}$

$=\frac{1}{\log {(x-1)}^2}$

$=\frac{1}{2\log (x-1)}$