Solve ${log}_{(x + 3)} (x^{2} - x) < 1$ .

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Solution

${log}_{(x + 3)} (x^{2} - x) < 1 (x^{2} - x) < {(x + 3)}^{1} x^{2} - x < x + 3 x^{2} - 2 x - 3 < 0 x^{2} - 3 x + x - 3 < 0 x (x - 3) + 1 (x - 3) < 0 (x + 1) (x - 3) < 0 ∴ x ϵ (- 1, 3)$

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