Solve :
$m + n = 12;$ $m - n = 10$

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Solution

Given the equations $m + n = 12;$ ......(1) and $m - n = 10$ ......(2).
Now adding (1) and (2) we get,
$2 m = 22$
or, $m = 11$ .
Again subtracting (2) from (1) we get,
$2 n = 2$
or, $n = 1$ .

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$m$	$12$	.....	$6$	.....
$n$	$10$	$4$	.....	$8$

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