Question

Solve
$\underset{x\to 0}{lim}\frac{x^2}{\sin x^2}$

Answer 1

$\underset{x\to 0}{lim}\frac{x^2}{\sin x^2}$

Apply $L$ Hospital rule

$\underset{x\to 0}{lim}\frac{2x}{2x\cos x^2}$

$\underset{x\to 0}{lim}\sec x^2$

$=1$