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Question

Solve limx1cos2cos2xx2|x|

A
2sin2
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B
2tan2
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C
sin2
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D
2cos2
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Solution

The correct option is A 2sin2
limx1cos2cos2xx2|x|=l (say ) [is of the form 00]
l=limx10+(sin2x)(2)2x+1(x1, |x|=x) [L' Hospital rule]
l=2sin(2)2+1
l=2sin2

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