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Byju's Answer
Standard XII
Mathematics
Algebra of Limits
Solve limx ...
Question
Solve
lim
x
→
−
1
x
2
−
x
−
2
(
x
2
+
x
)
+
sin
(
x
+
1
)
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Solution
lim
x
→
−
1
x
2
−
x
−
2
(
x
2
+
x
)
+
sin
(
x
+
1
)
it is of the form
0
0
So, we will apply L Hospital rule until we will get determinate form
Differentiating numerator and denominator we will get,
lim
x
→
−
1
2
x
−
1
2
x
+
1
+
cos
(
x
+
1
)
Differentiating numerator and denominator again we will get,
lim
x
→
−
1
2
2
−
sin
(
x
+
1
)
=
1
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0
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