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Question

Solve limx1x2x2(x2+x)+sin(x+1)

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Solution

limx1x2x2(x2+x)+sin(x+1)

it is of the form 00

So, we will apply L Hospital rule until we will get determinate form

Differentiating numerator and denominator we will get,
limx12x12x+1+cos(x+1)

Differentiating numerator and denominator again we will get,
limx122sin(x+1)=1

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