Question

Solve of simplify the following problem, using the properties of roots:
$\sqrt{150}-\sqrt{96}$

• A. $\sqrt{6}$
• B. $\sqrt{7}$
• C. $\sqrt{5}$
• D. $\sqrt{3}$

Answer 1

Answer: (A)

$\sqrt{6}$

$\sqrt{150}-\sqrt{96}=(\sqrt{25}\times \sqrt{6})-(\sqrt{16}\times \sqrt{6})=5\sqrt{6}-4\sqrt{6}=\sqrt{6}$