wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve of simplify the following problem, using the properties of roots:
x2y3+3x2y3
assuming x and y are positive

A
3xyy
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2xyx
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2x2yy
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2xyy
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is B 2xyy
2xyy: Notice that you have two terms under the radical that both contain x2y3. You can add like terms together if they are under the same radical: x2y3+3x2y3=(1+3)x2y3=4x2y3. Now factor out all squares and isolate them under their own radical sign:
4x2y3=4×x2×y2×y=2xyy
(Note since x and y are positive x2=x and y2=y)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Methods of Solving First Order, First Degree Differential Equations
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon