Solve of simplify the following problem, using the properties of roots: √x2y3+3x2y3 assuming x and y are positive
A
3xy√y
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B
2xy√x
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C
2x2y√y
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D
2xy√y
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Solution
The correct option is B2xy√y
2xy√y: Notice that you have two terms under the radical that both contain x2y3. You can add like terms together if they are under the same radical: √x2y3+3x2y3=√(1+3)x2y3=√4x2y3. Now factor out all squares and isolate them under their own radical sign: