Question

Solve: $\stackrel{3}{\underset{0}{\int }}(e^x+6)dx$

Answer 1

${\int }_0^3(e^x+6)dx$

$=e^x{|}^3+6x{|}^3$

$=(e^3-e^0{)}^0+(18{-}^{\circ }0)$

$=e^3-1+18$

$=e^3+17$

$\therefore {\int }_0^3(e^x+6)dx=e^3+17$