Solve-p - p - 1-2 - 1 - p - 2-3 -2 MARKS-

Concept: 1 Mark Application: 1 Mark p p 1/2 = 1 p 2/3 (2p – p + 1)/2 = (3 – p + 2)/3 3p + 3 = 10 – 2p 5p = 7 p = 7/5 ...

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Standard VIII

Mathematics

Reducing Equations to Simpler Form

Solve:p - p -...

Question

Solve:
$p - \frac{p - 1}{2} = 1 - \frac{p - 2}{3}$ [2 MARKS]

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Solution

Concept: 1 Mark
Application: 1 Mark

$p - \frac{p - 1}{2} = 1 - \frac{p - 2}{3}$

$\frac{(2 p - p + 1)}{2} = \frac{(3 - p + 2)}{3}$

$3 p + 3 = 10 - 2 p$

$5 p = 7$

$p = \frac{7}{5}$

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Solve: p−p−12=1−p−23 [2 MARKS]

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Solve:
$p - \frac{p - 1}{2} = 1 - \frac{p - 2}{3}$ [2 MARKS]

Concept: 1 Mark
Application: 1 Mark

$p - \frac{p - 1}{2} = 1 - \frac{p - 2}{3}$

$\frac{(2 p - p + 1)}{2} = \frac{(3 - p + 2)}{3}$

$3 p + 3 = 10 - 2 p$

$5 p = 7$

$p = \frac{7}{5}$