Solve Q 21.
21. A power company burns approximately 474 tons of coal per day to produce electricity. If the sulphur content of the coal is 1.30 % by weight, how many tons $S O_{2}$ are dumped into the atmosphere each day?

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Solution

Dear student

$474 t o n n e s c o a l w i l l c o n t a i n S = \frac{1.3}{100} \times 474 t o n n e s = \frac{1.3 \times 474}{100} \times 10^{6} g m o l e s o f S = \frac{1.3 \times 474}{100 \times 32} \times 10^{6} g S + O_{2} \to S O_{2} 1 m o l e S 1 m o l e o f S O_{2} m o l e s o f S O_{2} = m o l e s o f S M o l e s o f S O_{2} = \frac{1.3 \times 474}{100 \times 32} \times 64 \times 10^{6} g = 12.3 t o n n e s$

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Solve Q 21. 21. A power company burns approximately 474 tons of coal per day to produce electricity. If the sulphur content of the coal is 1.30 % by weight, how many tons SO2 are dumped into the atmosphere each day?

Dear student 474tonnes coal will contain S=1.3100×474 tonnes=1.3×474100×106 gmoles of S=1.3×474100×32×106 gS +O2→ SO21mole S 1 mole of SO2moles of SO2= moles of SMoles of SO2=1.3×474100×32× 64×106 g=12.3 tonnes Regards

Solve Q 21.
21. A power company burns approximately 474 tons of coal per day to produce electricity. If the sulphur content of the coal is 1.30 % by weight, how many tons $S O_{2}$ are dumped into the atmosphere each day?