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Question

Solve : Σnr=1(2r1)(2r+1)

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Solution

nr=1(2r1)(2r+1)nr=1(4r21)=4(n)(n+1)(2n+1)6n=2n(n+1)(2n+1)3n3=n3[2(n+1)(2n+1)3]=n3[4n2+6n1]

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