The correct option is
D (5,−4)Let
2x+y=6........(1)
and 7x+2y=27.......(2)
Multiply the (1) by 2
⇒4x+2y=12.......(3)
Subtract the (3) from (2), we get
⇒4x+2y=12
⇒7x+2y=27
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−3x=−15
⇒x=−15−3=5
Substitute the value of x=5 in (1)
⇒2×5+y=6
⇒10+y=6
⇒y=6−10=−4
So, x=5 and y=−4