We have,
sin105∘+cos105∘
⇒√2(1√2sin105∘+1√2cos105∘)
⇒√2(sin45∘sin105∘+cos45∘cos105∘)
⇒√2(cos105∘cos45∘+sin105∘sin45∘)
⇒√2cos(105∘−45∘)[∵cos(A−B)=cosAcosB+sinAsinB]
⇒√2cos60∘
⇒√2×12
⇒1√2
Hence, this is the answer.