wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve :sin2π8+sin23π8+sin25π8+sin27π8=2

Open in App
Solution

From question,
sin2π8+sin2(π2π8)+sin25π8+sin2(3π25π8)

=sin2π8+cos2π8+sin25π8+cos25π8 ......as.. (sin2θ+cos2θ=1)
=1+1
=2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Derivative from First Principles
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon