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Question

Solve :sin2π8+sin23π8+sin25π8+sin27π8=2

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Solution

From question,
sin2π8+sin2(π2π8)+sin25π8+sin2(3π25π8)

=sin2π8+cos2π8+sin25π8+cos25π8 ......as.. (sin2θ+cos2θ=1)
=1+1
=2

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