Solve- sin 2-3 - sin 22-3 - sin 25-3 - sin 28-3 - 3

sin^2π3+ sin^22π3+ sin^25π3 + sin^28π3 =( √(3)2)^2+ ( √(3)2)^2+sin^2( 2π π3) + sin^2(3 π π3) =34+34+ ( sinπ3)^2+ ( sin( π3) )^2 =34+34+34+3 ...

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Integration of Irrational Algebraic Fractions - 2

Solve: sin 2...

Question

Solve:
${sin}^{2} \frac{π}{3} + {sin}^{2} \frac{2 π}{3} + {sin}^{2} \frac{5 π}{3} + {sin}^{2} \frac{8 π}{3} = 3$

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Solution

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Similar questions

{sin}^{2} \frac{π}{7} . {sin}^{2} \frac{5 π}{14} . {sin}^{2} \frac{8 π}{7} . {sin}^{2} \frac{9 π}{14}

{sin}^{2} (\frac{2 π}{3}) + {cos}^{2} (\frac{5 π}{6}) - {tan}^{2} (\frac{3 π}{4}) =

{sin}^{2} \frac{π}{8} + {sin}^{2} \frac{3 π}{8} + {sin}^{2} \frac{5 π}{8} + {sin}^{2} \frac{7 π}{8}

{sin}^{2} (\frac{2 π}{3}) + {cos}^{2} (\frac{5 π}{6}) + {tan}^{2} (\frac{3 π}{4}) =

{⎡ ⎣ \begin{matrix} cos \frac{2 π}{3} & - sin \frac{2 π}{3} sin \frac{2 π}{3} & cos \frac{2 π}{3} \end{matrix} ⎤ ⎦}^{k} = [\begin{matrix} 1 & 0 0 & 1 \end{matrix}]

k

(k \neq 0)

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