Question

Solve: ${\sin }^2\theta +{\sin }^2\theta =1$ and find $\theta$.

Answer 1

$\begin{array}{c}{\sin }^2\theta +{\sin }^2\theta =1\\ 2{\sin }^2\theta =1\\ \sin \theta =\frac{1}{2}\\ \sin \theta =\frac{1}{\sqrt{2}}\\ \theta ={45}^0,\end{array}$