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Byju's Answer
Standard X
Mathematics
Range of Trigonometric Ratios from 0 to 90 Degrees
Solve: sin 7...
Question
Solve:
sin
75
o
+
sin
15
o
.
Open in App
Solution
sin
75
0
+
sin
15
0
⇒
sin
(
45
0
+
30
)
+
sin
(
45
0
+
30
0
)
⇒
sin
45
0
cos
30
0
+
cos
45
0
.
sin
30
0
+
sin
45
0
.
cos
30
0
−
cos
45
0
.
sin
30
0
⇒
2
sin
45
0
.
cos
30
0
=
2
×
1
√
2
×
√
3
2
=
√
3
2
A
n
s
.
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0
Similar questions
Q.
Solve:
sin
75
o
+
sin
15
o
cos
75
o
+
cos
15
o
=
Q.
cos
15
o
−
sin
15
o
cos
15
o
+
sin
15
o
=
1
√
3
Q.
Show that
cos
15
o
−
sin
15
o
cos
15
o
+
sin
15
o
=
1
√
3
Q.
The value of
cos
15
o
−
sin
15
o
cos
15
o
+
sin
15
o
is equal to
Q.
The value of
sin
75
o
=
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Range of Trigonometric Ratios from 0 to 90
MATHEMATICS
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Range of Trigonometric Ratios from 0 to 90 Degrees
Standard X Mathematics
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