Question

Solve $\sin \left(ax+b\right)\cos \left(ax+b\right)$

Answer 1

Multiplying and dividing by $2$ and we get,

$\sin (ax+b)\cos (ax+b)$

$=\frac{2\sin (ax+b)\cos (ax+b)}{2}\therefore \sin 2A=2\sin A\cos A$

$=\frac{1}{2}\sin 2(ax+b)$

Hence, this is the answer.