Solve : $s i n 60^{0} c o s 30^{0} + s i n 30^{0} c o s 60^{0}$

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Solution

$sin 60 ° cos 30 ° + sin 30 ° c o s 60 ° = \frac{\sqrt{3}}{2} \times \frac{\sqrt{3}}{2} + \frac{1}{2} \times \frac{1}{2} = \frac{3}{4} + \frac{1}{4} = \frac{4}{4} = 1$

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