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Question
Solve √24−10x=3−4x,3−4x>0
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Solution
Given √24−10x=3−4xSquaring on both sides, we get, 24−10x=(3−4x)2→16x2−14x−15=0→16x2−24x+10x−15=0→(8x+5)(2x−3)=0 which gives x=32 or −58When x=32,3−4x=3−4(32)<0 and hence, x=32 is not a solution of the equation. When x=−58,3−4x>0 and hence, the solution set is {−58}.
Given √24−10x=3−4x
Squaring on both sides, we get, 24−10x=(3−4x)2
→16x2−14x−15=0→16x2−24x+10x−15=0
→(8x+5)(2x−3)=0 which gives x=32 or −58
When x=32,3−4x=3−4(32)<0 and hence, x=32 is not a solution of the equation.
When x=−58,3−4x>0 and hence, the solution set is {−58}.
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