Question

Solve: $\sqrt{3}{x}^2+4x+\sqrt{3}=0$ ?

Answer 1

By using Quadratic formula;

Here, $a=\sqrt{3};b=4;c=\sqrt{3}$

$\because x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\Rightarrow x=\frac{-4\pm \sqrt{4^2-4.\sqrt{3}.\sqrt{3}}}{2.\sqrt{3}}\Rightarrow x=\frac{-4\pm 2}{2\sqrt{3}}\Rightarrow x=-\frac{1}{\sqrt{3}};-\sqrt{3}$