Solve:
$\sqrt[4]{27} \div \sqrt[4]{3}$

\sqrt[4]{9}

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\sqrt[4]{12}

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\sqrt[4]{6}

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\sqrt[4]{3}

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Solution

The correct option is A $\sqrt[4]{9}$
$\sqrt[4]{27} \div \sqrt[4]{3}$

$= \sqrt[4]{27 \div 3} = \sqrt[4]{9}$

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