√5(1+√5)x=2√5+4
x=(2√5+4√5(1+√5))
=2(√5+2√5(√5+1))(√5−1√5−1)
=2(5−√5+2√5−25−1)
=(3+√52)(√5√5)
=(3√5+510)
=(5+3√510)