MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Functions

Solve: √ 9+...

Question

Solve: $\sqrt{9 + 2 x} - \sqrt{2 x} = \frac{5}{\sqrt{9 + 2 x}}$

Open in App

Solution

$\sqrt{9 + 2 x} - \sqrt{2 x} = \frac{5}{\sqrt{9 + 2 x}}$
$\Rightarrow x \geq 0$ & $x \geq - 9 / 2$
$\Rightarrow 9 + 2 x - \sqrt{(9 + 2 x) 2 x} = 5$
$\Rightarrow 2 x + 4 = \sqrt{(9 + 2 x) 2 x}$
Squaring
$\Rightarrow 4 x^{2} + 16 x + 16 = (9 + 2 x) 2 x$
$\Rightarrow 4 x^{2} + 16 x + 16 = 4 x^{2} + 18 x$
$\Rightarrow x = 8$

Suggest Corrections

thumbs-up

1

Similar questions

x + 6 - 3 x - 5 - 2 (x - 5) = 2 x - 9 - 2 x + 5 - 3 (x + 1)

\frac{2 x}{9} = 5

Q. Solve the equation:

- (x - 5) + 5 (x - 9) = 2 (x + 8) - (2 x + 5)

.

\frac{3}{5} + 2 x = 9

\sqrt{9 - (2 x + 5)^{2}}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon