The correct option is B |(a^3 b^3)^2| √((a^3 b^3)^5a^3 b^3) = √((a^3 b^3)^4) = √(((a^3 b^3)^2)^2) = |(a^3 b^3)^2| ...

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Natural Numbers

solve: √a3-...

Question

solve: $\sqrt{\frac{(a^{3} - b^{3})^{5}}{a^{3} - b^{3}}}$

∣ ∣ (a^{3} + b^{3})^{2} ∣ ∣

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∣ ∣ (a^{3} - b^{3})^{3} ∣ ∣

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∣ ∣ (a^{3} - b^{3})^{2} ∣ ∣

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(a^{3} - b^{3})^{4}

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Solution

The correct option is B $∣ ∣ (a^{3} - b^{3})^{2} ∣ ∣$
$\sqrt{\frac{(a^{3} - b^{3})^{5}}{a^{3} - b^{3}}}$
$=$ $\sqrt{(a^{3} - b^{3})^{4}}$
$=$ $\sqrt{((a^{3} - b^{3})^{2})^{2}}$
$=$ $∣ ∣ (a^{3} - b^{3})^{2} ∣ ∣$

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Similar questions

|\begin{matrix} a^{2} & 2 a b & b^{2} \\ b^{2} & a^{2} & 2 a b \\ 2 a b & b^{2} & a^{2} \end{matrix}| = {(a^{3} + b^{3})}^{2}

∣ ∣ ∣ ∣ ∣ \begin{matrix} 2 a b & a^{2} & b^{2} a^{2} & b^{2} & 2 a b b^{2} & 2 a b & a^{2} \end{matrix} ∣ ∣ ∣ ∣ ∣ = - {(a^{3} + b^{3})}^{2} .

(a^{2} + b^{2})^{3} = (a^{3} + b^{3})^{2}

\frac{a}{b} + \frac{b}{a} =

a^{3} {(b - c)}^{3} + b^{3} {(c - a)}^{3} + c^{3} {(a - b)}^{3}

Solve:
$(a^{3} + 2) (a^{3} - 2) \div [(a^{3} - 2)] - a^{3}$

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