Solve:
$\sqrt{{(\frac{3}{4})}^{1 - 3 x}} = 2 \frac{10}{27}$

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Solution

or, $1 - 3 x = - 6$
or, $3 x = 7$
or, $x = \frac{7}{3}$ .

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Similar questions

{(\sqrt[3]{\frac{2}{3}})}^{x - 1} = \frac{27}{8}

4 \frac{1}{3} - \frac{3 x - 4}{5} = \frac{x - 7}{3}

\frac{1}{x} + a = 1

x = (2 x - \frac{3 x}{7}) - \frac{4 x - 27}{3} - 3

3 x = 27

4 \frac{1}{2} \times 4 \frac{1}{3} - 8 \frac{1}{3} \div 5 \frac{2}{3} = ? .

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