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Question

Solve:
nr=113+23+33+...+r3r(r+1)

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Solution

nr=113+23+33+.......+r3r(r+1)nr=1{12r(r+1)}2r(r+1)14nr=1r(r+1)14nr=1r2+14nr=1r14×16n(n+1(2n+1)+14×12n(n+1))124n(n+1)(2n+1)+18n(n+1)n(n+1)8[2n+1+33]2n(n+1)(n+2)24=n(n+1)(n+2)22.

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